Hello World

$$ \int_{a}^{b}x(t)dt = \dfrac{b - a}{N} \\ =\sum_{k=1}^{N}x(t_k)\cdot\dfrac{b-a}{N} $$

$$ \begin{aligned} \int_{a}^{b}x(t)dt &= \dfrac{b - a}{N} \\ &=\sum_{k=1}^{N}x(t_k)\cdot\dfrac{b-a}{N} \\ \end{aligned} $$

$$ \mathrm{Integrals\ are\ numerically\ approximated\ as\ finite\ series}:\\ \begin{split} \int_{a}^{b}x(t)dt &= \dfrac{b - a}{N} \\ &=\sum_{k=1}^{N}x(t_k)\cdot\dfrac{b-a}{N} \end{split} \\ where\ t_k = a + (b-a)\cdot k/N $$

$$ \begin{align*} p(x) = 3x^6 + 14x^5y &+ 590x^4y^2 + 19x^3y^3 \\ &- 12x^2y^4 - 12xy^5 + 2y^6 - a^3b^3 - a^2b - ab + c^5d^3 + c^4d^3 - cd \end{align*} $$

$$ \begin{split} &(X \in B) = X^{-1}(B) = {s \in S: X(s) \in B} \subset S \\ &\Rightarrow P(x \in B) = P({s \in S: X(s) \in B}) \end{split} $$

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let i: i32 = 13;
let v = vec![1, 2, 3, 4, 5, 65];
for x in v.iter() {
    println!("{}", x);
}

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typedef struct Block_t {
    int head;
    int data;
} Block_t;